问:sql查询某张表中某一列的重复数据?
答:1.sql查询某张表中某一列的重复数据 select 字段name from 表A where 字段name in (select 字段name from 表A group by 字段name having count(字段name)> 1) order by 字段name 2.sql 替换某一列的某几个值 update 表名 set 字段名 =replace(原字段名,被替换前的数值,替换后的数值) 例子: update 表A set age = replace(age,18,20)
问:用sql语句进行多表连接查询出现重复数据?
答:1、用select语句,查看两个表中的数据,确认下来的结果是每个表中都只有两行数据; 2、尝试着用最常用的两表结合查询方式来看看结果----结果重复出现,并且结果错误:select a.pono,a.p_name,a.p_kg as 系统重量,b.p_kg as 实际重量 from test1 a,test2 b where a.pono=b.sono; 3、执行完整代码,可以得出结果,select isnull(a.pono,b.sono) as pono,isnull(a.p_name,b.p_name)
问:sql查找某一字段相同的所有数据?
例如表中有三个字段 id name age
1 陈 15
2 张 15
3 李 14
4 王 14
找出所有age相同的数据的sql语句该怎么写?
答:使用sql模糊查询语句就能够实现;模糊语句的查询模糊条件对应的对象字段是不分前后模糊的,只要内容中有这个字符都能够模糊查询出来。 sql模糊语法:select * from 表名 where
答:1、可以使用WHERE子句进行查询。 2、如要查询t1表中name字段为张三的所有数据,可以使用以下语句。 3、语句为: SELECT * FROM t1 WHERE name = '张三'
答:你的问题看不懂。 1。查询某个age=15相同的数据 select * from table where age = 15 2。查询各个age相同的数据 select * from table order by age
答:select *from 此表 as A join (select count(age) from 此表 group by age) B on A.age=B.age 这样按相同年龄记录分类显示出来
答:Select * From 数据表 Where age in ( select age From 数据表 Group By age Having Count(age )>1)
问:SQL怎样查询重复数据?
答:selectid,name,memo fromA whereidin(selectidfromAgroupbyidhavingcount(1)>=2) 1查询 abcd相同的记录: select * from F where a=b and b=c and c=d 2查询有重复数据的记录 select * from F group by a,b,c,d having count(*)>1 3取出数据过滤到重复的数据 select distinct a,b,c,d from f
问:SQL查询重复项目?
我想在数据库里查询重复了超过10次的条目,想了半天不知道SQL怎么写?帮帮我吧 都回答的挺好,但是我又出现了一个新问题,在mfc中使用odbc连接数据库的时候,究竟怎样执行我写好的sql语句?执行后结果又存在哪? 再加10分吧
答:sql不支持判断,查询重复的sql语句是: select " & ftabnm & ".bsm from " & ftabnm & " right join[select bsm from " & ftabnm & " group by bsm having count(bsm)>1]. as t on " & ftabnm & ".bsm" & " = t.bsm 至于结果可通过数据集查询记录数来判断.
问:sql查询按两个字段查询重复记录?
我想查询表shiyan003,按xm,sfzhm这两个字段查
select * from shiyan003 a
where (a.xm,a.sfzhm) in (select xm,sfzhm from shiyan003 group by xm,sfzhm having count(*) > 1)
提示:第2行 ',' 附近有语法错误。怎么改呢
答:1、改成如下语句: select shiyan003.* from shiyan003 right join (select xm,sfzhm from shiyan003 group by xm,s
答:应该是in关键字不支持多字段吧,你这样试一下 select * from shiyan003 a where exists (select 1 from (select xm, sfzhm from shiyan003 group by xm, sfzhm
答:select * from shiyan003 a where exists (select 1 from (select xm, sfzhm from shiyan003 group by xm, sfzhm havi
答:select * from shiyan003 a where a.xm in (select xm from shiyan003 group by xm,sfzhm having count(*) > 1) and a.sfzhm in (select sfzhm from shiyan003 group by xm,sfzhm having
答:这样肯定有错的你看看IN (SELECT XM FROM SHIYAN003)一个IN只能一个字段。 SELECT COUNT(1) FROM SHIYAN003 A GROUP BY A.XM,A.SFZHM HAVING COUNT(1) > 1